Johnson Island (Antarctica)
  Johnson Island Location in Antarctica | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 72°52′S 93°54′W / 72.867°S 93.900°WCoordinates: 72°52′S 93°54′W / 72.867°S 93.900°W |
| Administration | |
|
None | |
| Demographics | |
| Population | Uninhabited |
| Additional information | |
| Administered under the Antarctic Treaty System | |
Johnson Island is an ice-covered island, about 17 kilometres (9 nmi) long and 9 kilometres (5 nmi) wide, lying within the Abbot Ice Shelf, Antarctica, about 26 kilometres (14 nmi) southeast of Dustin Island. The feature was observed and roughly positioned as an "ice rise" by parties from the USS Glacier (AGB-4) in February 1961. It was remapped by the United States Geological Survey from U.S. Navy air photos, 1966, and was named by the Advisory Committee on Antarctic Names for Theodore L. Johnson, an electrical engineer at Byrd Station in 1964–65.[1]
See also
References
- ↑ "Johnson Island". Geographic Names Information System. United States Geological Survey. Retrieved 2012-07-27.
This article incorporates public domain material from the United States Geological Survey document "Johnson Island" (content from the Geographic Names Information System).