Berezinian

In mathematics and theoretical physics, the Berezinian or superdeterminant is a generalization of the determinant to the case of supermatrices. The name is for Felix Berezin. The Berezinian plays a role analogous to the determinant when considering coordinate changes for integration on a supermanifold.

Definition

The Berezinian is uniquely determined by two defining properties:

• $\operatorname {Ber}(XY)=\operatorname {Ber}(X)\operatorname {Ber}(Y)$
• $\operatorname {Ber}(e^{X})=e^{{\operatorname {str(X)}}}\,$

where str(X) denotes the supertrace of X. Unlike the classical determinant, the Berezinian is defined only for invertible supermatrices.

The simplest case to consider is the Berezinian of a supermatrix with entries in a field K. Such supermatrices represent linear transformations of a super vector space over K. A particular even supermatrix is a block matrix of the form

$X={\begin{bmatrix}A&0\\0&D\end{bmatrix}}$

Such a matrix is invertible if and only if both A and D are invertible matrices over K. The Berezinian of X is given by

$\operatorname {Ber}(X)=\det(A)\det(D)^{{-1}}$

For a motivation of the negative exponent see the substitution formula in the odd case.

More generally, consider matrices with entries in a supercommutative algebra R. An even supermatrix is then of the form

$X={\begin{bmatrix}A&B\\C&D\end{bmatrix}}$

where A and D have even entries and B and C have odd entries. Such a matrix is invertible if and only if both A and D are invertible in the commutative ring R₀ (the even subalgebra of R). In this case the Berezinian is given by

$\operatorname {Ber}(X)=\det(A-BD^{{-1}}C)\det(D)^{{-1}}$

or, equivalently, by

$\operatorname {Ber}(X)=\det(A)\det(D-CA^{{-1}}B)^{{-1}}.$

These formulas are well-defined since we are only taking determinants of matrices whose entries are in the commutative ring R₀. The matrix

$D-CA^{{-1}}B\,$

is known as the Schur complement of A relative to ${\begin{bmatrix}A&B\\C&D\end{bmatrix}}.$

An odd matrix X can only be invertible if the number of even dimensions equals the number of odd dimensions. In this case, invertibility of X is equivalent to the invertibility of JX, where

$J={\begin{bmatrix}0&I\\-I&0\end{bmatrix}}.$

Then the Berezinian of X is defined as

$\operatorname {Ber}(X)=\operatorname {Ber}(JX)=\det(C-DB^{{-1}}A)\det(-B)^{{-1}}.$

Properties

• The Berezinian of X is always a unit in the ring R₀.
• $\operatorname {Ber}(X)^{{-1}}=\operatorname {Ber}(X^{{-1}})$
• $\operatorname {Ber}(X^{{st}})=\operatorname {Ber}(X)$ where $X^{{st}}$ denotes the supertranspose of X.
• $\operatorname {Ber}(X\oplus Y)=\operatorname {Ber}(X){\mathrm {Ber}}(Y)$

Berezinian module

The determinant of an endomorphism of a free module M can be defined as the induced action on the 1-dimensional highest exterior power of M. In the supersymmetric case there is no highest exterior power, but there is a still a similar definition of the Berezinian as follows.

Suppose that M is a free module of dimension (p,q) over R. Let A be the (super)symmetric algebra S*(M*) of the dual M* of M. Then an automorphism of M acts on the ext module

$Ext_{{A}}^{p}(R,A)$

(which has dimension (1,0) if q is even and dimension (0,1) if q is odd)) as multiplication by the Berezianian.

See also

• Berezin integration

References

• Berezin, Feliks Aleksandrovich (1966) [1965], The method of second quantization, Pure and Applied Physics, 24, Boston, MA: Academic Press, ISBN 978-0-12-089450-5, MR 0208930
• Deligne, Pierre; Morgan, John W. (1999), "Notes on supersymmetry (following Joseph Bernstein)", in Deligne, Pierre; Etingof, Pavel; Freed, Daniel S.; Jeffrey, Lisa C.; Kazhdan, David; Morgan, John W.; Morrison, David R.; Witten., Edward, Quantum fields and strings: a course for mathematicians, Vol. 1, Providence, R.I.: American Mathematical Society, pp. 41–97, ISBN 978-0-8218-1198-6, MR 1701597
• Manin, Yuri Ivanovich (1997), Gauge Field Theory and Complex Geometry (2nd ed.), Berlin, New York: Springer-Verlag, ISBN 978-3-540-61378-7