1998 Singapore Open – Doubles

Doubles
1998 Singapore Open
Champions Australia Todd Woodbridge
Australia Mark Woodforde[1]
Runners-up India Mahesh Bhupathi
India Leander Paes
Final score 6–2, 6–3

The 1998 Singapore Open was a men's tennis tournament played on Indoor Hard in Singapore, Singapore that was part of the Championship Series of the 1998 ATP Tour. It was the seventh edition of the tournament and was held from 12 October – 18 October.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

Draw

Key

Finals

First RoundQuarterfinalsSemifinalsFinal[1]
1 Australia T Woodbridge
Australia M Woodforde
6 5 6
United States J Courier
United States J-M Gambill
4 7 1 1 Australia T Woodbridge
Australia M Woodforde
6 7
South Africa L Bale
South Africa B Haygarth
6 4 6 South Africa L Bale
South Africa B Haygarth
2 6
Croatia S Hiršzon
Croatia G Ivanišević
3 6 4 1 Australia T Woodbridge
Australia M Woodforde
2 7 6
United States J Gimelstob
United States J Stark
2 6 6 United States J Gimelstob
United States J Stark
6 6 4
4 United States P Galbraith
New Zealand B Steven
6 3 4 United States J Gimelstob
United States J Stark
7 7
Czech Republic M Damm
Australia P Tramacchi
7 6 Czech Republic M Damm
Australia P Tramacchi
6 6
Thailand P Srichaphan
Netherlands R Wassen
5 4 1 Australia T Woodbridge
Australia M Woodforde
6 6
Romania A Pavel
Armenia S Sargsian
6 6 2 India M Bhupathi
India L Paes
2 3
Zimbabwe W Black
South Africa M Ondruska
0 3 Romania A Pavel
Armenia S Sargsian
6 1 6
3 Canada S Lareau
Canada D Nestor
6 6 3 Canada S Lareau
Canada D Nestor
3 6 3
Australia M Tebbutt
Sweden M Tillström
3 4 Romania A Pavel
Armenia S Sargsian
6 4
Finland T Ketola
Italy L Ketola
3 6 7 2 India M Bhupathi
India L Paes
7 6
Germany K Braasch
Germany M Kohlmann
6 4 6 Finland T Ketola
Italy L Ketola
3 3
2 India M Bhupathi
India L Paes
7 6 2 India M Bhupathi
India L Paes
6 6
United States M Keil
United States TJ Middleton
6 4

References

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