1990 FIFA World Cup qualification (CONMEBOL)

The South American (CONMEBOL) zone of qualification for the 1990 FIFA World Cup saw 9 teams competing for 2 direct places at the finals, with one extra place potentially on offer to the winner of a play-off. CONMEBOL member Argentina qualified automatically as reigning World Cup champions.

Format

Teams were divided into 3 groups of 3 teams each. The teams would play against each other on a home-and-away basis. The 2 group winners with the best record would qualify. The group winner with the worst record would advance to the CONMEBOL / OFC Intercontinental Play-off.

Draw

The draw for the qualifying groups took place in Zürich, Switzerland on 12 December 1987. During the draw teams were drawn from 3 seeded pots into the 3 qualifying groups.

Pot A Pot B Pot C

 Brazil
 Paraguay
 Uruguay

 Chile
 Colombia
 Peru

 Bolivia
 Ecuador
 Venezuela

Group 1

Pld W D L GF GA GD Pts
 Uruguay 430172+56
 Bolivia 430165+16
 Peru 40042860
  Bolivia Peru Uruguay
 BOL 2–1 2–1
 PER 1–2 0–2
 URU 2–0 2–0

Uruguay qualified with the second-best record among the group winners.

Group 2

Pld W D L GF GA GD Pts
 Colombia 421153+25
 Paraguay 42026714
 Ecuador 41124513
  Colombia Ecuador Paraguay
 COL 2–0 2–1
 ECU 0–0 3–1
 PAR 2–1 2–1

Colombia advanced to the CONMEBOL / OFC Intercontinental Play-off with the worst record among the group winners.

Group 3

Pld W D L GF GA GD Pts
 Brazil 4310131+127
 Chile 421194+55
 Venezuela 4004118170
  Brazil Chile Venezuela
 BRA 2–0 6–0
 CHI 1–1 5–0
 VEN 0–4 1–3

Brazil qualified with the best record among the group winners.

Notes

    External links

    This article is issued from Wikipedia - version of the 12/14/2015. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.