Allen Township, Hancock County, Ohio

Allen Township, Hancock County, Ohio
Township


Location of Allen Township in Hancock County.
Coordinates: 41°7′13″N 83°38′51″W / 41.12028°N 83.64750°W / 41.12028; -83.64750Coordinates: 41°7′13″N 83°38′51″W / 41.12028°N 83.64750°W / 41.12028; -83.64750
Country United States
State Ohio
County Hancock
Area
  Total 23.9 sq mi (61.8 km2)
  Land 23.7 sq mi (61.5 km2)
  Water 0.1 sq mi (0.3 km2)
Elevation[1] 794 ft (242 m)
Population (2000)
  Total 2,110
  Density 88.8/sq mi (34.3/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
FIPS code 39-01308[2]
GNIS feature ID 1086238[1]

Allen Township is one of the seventeen townships of Hancock County, Ohio, United States. The 2000 census found 2,110 people in the township, 1,797 of whom lived in the unincorporated portions of the township.[3]

Geography

Located in the northern part of the county, it borders the following townships:

Several populated places are located in Allen Township:

Name and history

Statewide, other Allen Townships are located in Darke, Ottawa, and Union counties.[4]

Government

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[5] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

References

External links

This article is issued from Wikipedia - version of the 10/10/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.