United States presidential election in Montana, 1948

Main article: United States presidential election, 1948



Nominee	Harry S. Truman	Thomas E. Dewey
Party	Democratic	Republican
Home state	Missouri	New York
Running mate	Alben W. Barkley	Earl Warren
Electoral vote	4	0
Popular vote	119,071	96,770
Percentage	53.1%	43.2%

County results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

Elections in Montana

Federal government

Presidential Elections
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Presidential Primaries
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U. S. Senate elections
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State government

Gubernatorial elections
1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016

Ballot measures

2004: Initiative 96

The 1948 United States presidential election in Montana took place on November 2, 1948, throughout the continuous 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana voted for the Democratic nominee, President Harry Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a large margin of 9.94%.

Results

United States presidential ^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Harry Truman (incumbent)	119,071	53.09%	4
	Republican	Thomas E. Dewey	96,770	43.15%	0
	Progressive	Henry Wallace	7,313	3.26%	0
	Socialist	Norman Thomas	695	0.31%	0
	Prohibition	Claude Watson	429	0.19%	0

References

↑ http://uselectionatlas.org/RESULTS/index.html

State Results of the 1948 U.S. presidential election

Candidates	Harry S. Truman Thomas E. Dewey Strom Thurmond Henry A. Wallace Norman Thomas Full list

General articles	Election timeline Democratic primaries Republican primaries Republican Convention Democratic Convention Debates

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Other 1948 elections	House Senate Gubernatorial

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