United States presidential election in Montana, 1896

United States presidential election in Montana, 1896
Montana
November 3, 1896 (1896-11-03)

 
Nominee William Jennings Bryan William McKinley
Party Democratic Republican
Home state Nebraska Ohio
Running mate Arthur Sewall Garret Hobart
Electoral vote 3 0
Popular vote 42,628 10,509
Percentage 79.93% 19.71%

County results

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Montana took place on November 3, 1896 throughout 45 states. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana overwhelmingly voted for the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan over the Republican nominee, former governor of Ohio William McKinley. Bryan won Montana by a landslide margin of 60.22%.

Bryan's support for many Populist goals resulted in him being nominated by both the Democratic Party and the People's Party (Populists), though with different running mates. One electoral vote from Montana was cast for the Populist Bryan-Watson ticket with Thomas E. Watson as Vice-President and two votes were cast for the Bryan-Sewall ticket.

Results

United States presidential [1]
Party Candidate Votes Percentage Electoral votes
Democratic William Jennings Bryan 42,628 79.93% 3
Republican William McKinley 10,509 19.71% 0
Prohibition Joshua Levering 193 0.36% 0

References

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