United States presidential election in Oklahoma, 1992

United States presidential election in Oklahoma, 1992

November 3, 1992

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 8 0 0 Popular vote 592,929 473,066 319,878 Percentage 42.7% 34.0% 23.0%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Oklahoma took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Oklahoma was won by incumbent President George H.W. Bush (R-Texas) with 42.65% of the popular vote over Governor Bill Clinton (D-Arkansas) with 34.02%. Businessman Ross Perot (I-Texas) finished in third with 23.01% of the popular vote.^[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.^[2]

Results

United States presidential election in Oklahoma, 1992[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H.W. Bush (incumbent)	592,929	42.65%	8
	Democratic	Bill Clinton	473,066	34.02%	0
	Independent	Ross Perot	319,878	23.01%	0
	Libertarian	Andre Marrou	4,486	0.32%	0
Totals			1,390,359	100.0%	8

References

1. "1992 Presidential General Election Results - Oklahoma". U.S. Election Atlas. Retrieved 8 June 2012.
2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.