United States presidential election in Virginia, 1992

United States presidential election in Virginia, 1992

November 3, 1992

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 13 0 0 Popular vote 1,150,517 1,038,650 348,639 Percentage 45.0% 40.6% 13.6%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Virginia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose thirteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia was won by incumbent President George H.W. Bush (R-Texas) with 44.97% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.59%. Businessman Ross Perot (I-Texas) finished in third with 13.63% of the popular vote.^[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.^[2]

Results

United States presidential election in Virginia, 1992[1][3]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H.W. Bush (inc.)	1,150,517	44.97%	13
	Democratic	Bill Clinton	1,038,650	40.59%	0
	Independent	Ross Perot	348,639	13.63%	0
	Democrats for Economic Recovery	Lyndon LaRouche	11,937	0.47%	0
	Libertarian	Andre Marrou	5,730	0.22%	0
	New Alliance Party	Lenora Fulani	3,192	0.12%	0
Totals			2,558,665	100.0%	13

References

1. "1992 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 10 June 2012.
2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 10 June 2012.
3. http://clerk.house.gov/member_info/electionInfo/1992election.pdf