Sanford, New York

Sanford, New York
Town
Sanford

Location within the state of New York

Coordinates: 42°4′52″N 75°28′46″W / 42.08111°N 75.47944°W / 42.08111; -75.47944Coordinates: 42°4′52″N 75°28′46″W / 42.08111°N 75.47944°W / 42.08111; -75.47944
Country United States
State New York
County Broome
Government
  Type Town Council
  Town Supervisor Dewey A. Decker
  Town Council
Area
  Total 91.0 sq mi (235.7 km2)
  Land 90.1 sq mi (233.4 km2)
  Water 0.9 sq mi (2.4 km2)
Elevation 1,148 ft (350 m)
Population (2010)
  Total 2,407
  Density 27/sq mi (10.3/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
ZIP code 13754
Area code(s) 607
FIPS code 36-65112
GNIS feature ID 0979457

Sanford is a town in Broome County, New York, United States. The population was 2,407 at the 2010 census.[1]

The town is on the east border of the county and the south border of the state of New York. Sanford is east of Binghamton.

History

Early ownership of the area was primarily divided into the Livingstone patent, the Fisher and Norton tract, and the Randolph patent. The region was first settled around 1787.

The town of Sanford was formed in 1821 from the town of Windsor.

Geography

According to the United States Census Bureau, the town has a total area of 91.0 square miles (235.7 km2), of which 90.1 square miles (233.4 km2) is land and 0.93 square miles (2.4 km2), or 1.01%, is water.[1]

The east town line is the border of Delaware County, the north town line is the border of Chenango County, and the south town line is the border of Pennsylvania, bordering Wayne and Susquehanna counties.

New York Route 17 crosses the town. New York State Route 41 intersects NY-17 west of McClure. The part of NY-17 near Deposit was one of the last sections to be completed in this part of New York, forcing travelers to exit at Deposit.

The West Branch of the Delaware River forms part of the eastern border of the town.

Demographics

Historical population
Census Pop.
1830931
18401,17326.0%
18502,508113.8%
18603,06122.0%
18703,2496.1%
18803,4957.6%
18903,265−6.6%
19003,5147.6%
19102,980−15.2%
19202,681−10.0%
19302,538−5.3%
19402,502−1.4%
19502,416−3.4%
19602,4893.0%
19702,5281.6%
19802,6354.2%
19902,576−2.2%
20002,477−3.8%
20102,407−2.8%
Est. 20142,381[2]−1.1%
U.S. Decennial Census[3]

As of the census[4] of 2000, there were 2,477 people, 983 households, and 694 families residing in the town. The population density was 27.5 people per square mile (10.6/km²). There were 1,545 housing units at an average density of 17.2 per square mile (6.6/km²). The racial makeup of the town was 98.26% White, 0.48% African American, 0.08% Native American, 0.24% Asian, 0.52% from other races, and 0.40% from two or more races. Hispanic or Latino of any race were 2.10% of the population.

There were 983 households out of which 30.5% had children under the age of 18 living with them, 56.6% were married couples living together, 8.5% had a female householder with no husband present, and 29.3% were non-families. 24.6% of all households were made up of individuals and 11.7% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 2.99.

In the town the population was spread out with 25.2% under the age of 18, 7.3% from 18 to 24, 23.9% from 25 to 44, 27.9% from 45 to 64, and 15.7% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 101.1 males. For every 100 females age 18 and over, there were 98.7 males.

The median income for a household in the town was $33,309, and the median income for a family was $40,472. Males had a median income of $31,344 versus $20,365 for females. The per capita income for the town was $17,083. About 12.9% of families and 15.6% of the population were below the poverty line, including 22.7% of those under age 18 and 9.0% of those age 65 or over.

Communities and locations in Sanford

References

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