United States presidential election in Louisiana, 1988

United States presidential election in Louisiana,1988

November 8, 1988

Nominee George H.W. Bush Michael Dukakis Party Republican Democratic Home state Texas Massachusetts Running mate Dan Quayle Lloyd Bentsen Electoral vote 10 0 Popular vote 883,702 717,460 Percentage 54.3% 44.1%

County Results   Dukakis—60-70%   Dukakis—50-60%   Dukakis—<50%   Bush—<50%   Bush—50-60%   Bush—60-70%   Bush—70-80%

President before election Ronald Reagan Republican Elected President George H.W. Bush Republican

Bush at the 1988 Republican National Convention, in New Orleans.

The 1988 United States presidential election in Louisiana took place on November 8, 1988 throughout all 50 states and D.C., which was part of the 1988 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana strongly voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts governor Michael Dukakis. The margin was 10%, which was the closest southern state margin, and the best Southern state showing for Dukakis.

Results

United States presidential election in Louisiana, 1988[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H. W. Bush	883,702	54.27%	10
	Democratic	Michael Dukakis	717,460	44.06%	0
	America First	David Duke	18,612	1.14%	0
	Libertarian	Ron Paul	4,115	0.25%	0
	New Alliance	Lenora Fulani	2,355	0.14%	0
	Democrats for Economic Recovery	Lyndon LaRouche	1,958	0.12%	0
Invalid or blank votes					—
Totals			1,628,202	100.00%	10
Voter turnout					—

References

1. "1988 Presidential General Election Results - Louisiana". Dave Leip's U.S. Election Atlas. Retrieved 2008-08-25.