United States presidential election in Maryland, 1988

United States presidential election in Maryland, 1988

November 8, 1988

Nominee George H. W. Bush Michael Dukakis Party Republican Democratic Home state Texas Massachusetts Running mate Dan Quayle Lloyd Bentsen Electoral vote 10 0 Popular vote 876,167 826,304 Percentage 51.11% 48.20%

County Results   Dukakis—70-80%   Dukakis—60-70%   Dukakis—50-60%   Bush—50-60%   Bush—60-70%   Bush—70-80%

President before election Ronald Reagan Republican Elected President George H.W. Bush Republican

The 1988 United States presidential election in Maryland took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland was won by Vice President George H.W. Bush (R-Texas), with 51.11% of the popular vote, over Massachusetts Governor Mike Dukakis (D-Massachusetts) with 48.20% of the popular vote.^[1] Bush ultimately won the national vote, defeating Governor Dukakis.^[2]

Results

United States presidential election in Maryland, 1988[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H.W. Bush	876,167	51.11%	10
	Democratic	Mike Dukakis	826,304	48.20%	0
	Libertarian	Ron Paul	6,748	0.39%	0
	New Alliance	Lenora Fulani	5,115	0.29%	0
	N/A	Write-ins	24	<0.01%	0
Totals			1,714,358	100.0%	10

References

1. "1988 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 8 June 2012.
2. "1988 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.