United States presidential election in Virginia, 1896
Main article: United States presidential election, 1896
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Elections in Virginia | ||||||||||
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The 1896 United States presidential election in Virginia took place on November 3, 1896, as part of the 1896 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.
Virginia voted for the Democratic and Populist candidate, former U.S. Representative William J. Bryan over the Republican candidate, Ohio Governor William McKinley. Bryan won the state by a margin of 6.56%.
Results
United States presidential election in Virginia, 1896[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic/Populist | William J. Bryan | 154,708 | 52.50% | 12 | |
Republican | William McKinley | 135,379 | 45.94% | 0 | |
Prohibition | Joshua Levering | 2,350 | 0.80% | 0 | |
National Democratic | John M. Palmer | 2,129 | 0.72% | 0 | |
Socialist Labor | Charles Matchett | 108 | 0.04% | 0 | |
Totals | 294,674 | 100.0% | 12 | ||
References
- ↑ "1896 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.
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