United States presidential election in Virginia, 1896

United States presidential election in Virginia, 1896
Virginia
November 3, 1896

 
Nominee William J. Bryan William McKinley
Party Democratic Republican
Home state Nebraska Ohio
Running mate Arthur Sewall Garret Hobart
Electoral vote 12 0
Popular vote 154,708 135,379
Percentage 52.50% 45.94%

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Virginia took place on November 3, 1896, as part of the 1896 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia voted for the Democratic and Populist candidate, former U.S. Representative William J. Bryan over the Republican candidate, Ohio Governor William McKinley. Bryan won the state by a margin of 6.56%.

Results

United States presidential election in Virginia, 1896[1]
Party Candidate Votes Percentage Electoral votes
Democratic/Populist William J. Bryan 154,708 52.50% 12
Republican William McKinley 135,379 45.94% 0
Prohibition Joshua Levering 2,350 0.80% 0
National Democratic John M. Palmer 2,129 0.72% 0
Socialist Labor Charles Matchett 108 0.04% 0
Totals 294,674 100.0% 12

References

  1. "1896 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.
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