Jefferson Township, Fayette County, Ohio

Jefferson Township, Fayette County, Ohio
Township

Countryside in western Jefferson Township

Location of Jefferson Township in Fayette County
Coordinates: 39°39′7″N 83°34′20″W / 39.65194°N 83.57222°W / 39.65194; -83.57222Coordinates: 39°39′7″N 83°34′20″W / 39.65194°N 83.57222°W / 39.65194; -83.57222
Country United States
State Ohio
County Fayette
Area
  Total 61.1 sq mi (158.2 km2)
  Land 61.0 sq mi (158.0 km2)
  Water 0.08 sq mi (0.2 km2)
Elevation[1] 1,050 ft (320 m)
Population (2010)
  Total 2,636
  Density 43/sq mi (16.7/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
FIPS code 39-38598[2]
GNIS feature ID 1086089[1]

Jefferson Township is one of the ten townships of Fayette County, Ohio, United States. As of the 2010 census the population was 2,636,[3] of whom 1,419 lived in the unincorporated portions of the township.[4]

Geography

Located in the northwestern corner of the county, it borders the following townships:

Two villages are located in Jefferson Township: Jeffersonville, the second largest municipality in Fayette County, in the center, and part of Octa in the southwest.

Name and history

It is one of twenty-four Jefferson Townships statewide.[5]

Government

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[6] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

References

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