United States presidential election in Delaware, 1836

United States presidential election in Delaware, 1836

November 3 – December 7, 1836

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate Francis Granger Richard Johnson Electoral vote 3 0 Popular vote 4,736 4,154 Percentage 53.24% 46.70%

The 1836 United States presidential election in Delaware took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Delaware by a margin of 6.54%.

Results

United States presidential election in Delaware, 1836[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	William Henry Harrison	4,736	53.24%	3
	Democratic	Martin Van Buren	4,154	46.70%	0
	N/A	Other	5	0.06%	0
Totals			8,895	100.0%	3

References

1. "1836 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 4 August 2012.