United States presidential election in Vermont, 1836

November 3 - December 7, 1836

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

Presidential General Elections
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Presidential Primaries
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Gubernatorial elections
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2012
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2006

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The 1836 United States presidential election in Vermont took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 19.86%.

Results

United States presidential election in Vermont, 1836^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	20,994	59.93%	7	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	14,037	40.07%	0	0.00%
Total				35,031	100.00%	7	100.00%

State Results of the 1836 U.S. presidential election

Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1836 elections	House Senate Gubernatorial

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