United States presidential election in New Jersey, 1836

November 3 - December 7, 1836

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

Presidential elections
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Primary elections
Democratic 2004 2008 Republican 2008 2012
United States Senate elections
1982 1988 1990 1994 1996 2000 2002 2006 2008 2012 2013 2014
Congressional elections
AL (1795) 1798 AL (1808) AL (1810) AL (1814) AL (1821) AL (1828) 2006 5^th 13^th 2008 7^th 2010 2012 10^th 2014 2016

Mayoral Elections
2014

Mayoral elections
2001 2004 2005 2009 2013

City elections
2005

The 1836 United States presidential election in New Jersey took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Jersey by a margin of 1.06%.

Results

United States presidential election in New Jersey, 1836^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	26,137	50.53%	8	100.00%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	25,592	49.47%	0	0.00%
Total				51,729	100.00%	8	100.00%

State Results of the 1836 U.S. presidential election

Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1836 elections	House Senate Gubernatorial

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