United States presidential election in Pennsylvania, 1836

November 3 – December 7, 1836

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

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The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a margin of 2.36%.

Results

United States presidential election in Pennsylvania, 1836^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	91,457	51.18%	30
	Whig	William Henry Harrison	87,235	48.82%	0
Totals			178,692	100.0%	30

State Results of the 1836 U.S. presidential election

Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1836 elections	House Senate Gubernatorial

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