United States presidential election in New York, 1836

November 3 - December 7, 1836

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

Presidential elections
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New York gubernatorial elections
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State Assembly elections
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Mayoral elections
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2009 2013
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2009 2013
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2013
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Mayoral elections
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Mayoral elections
2009

The 1836 United States presidential election in New York took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose forty-two representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New York by a margin of 9.26%.

Results

United States presidential election in New York, 1836^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	166,795	54.63%	42	100.00%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	138,548	45.37%	0	0.00%
Total				305,343	100.00%	42	100.00%

State Results of the 1836 U.S. presidential election

Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1836 elections	House Senate Gubernatorial

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