United States presidential election in Maine, 1840

United States presidential election in Maine, 1840

October 30 - December 2, 1844

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 7 0 Popular vote 46,612 46,190 Percentage 50.23 49.77

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

The 1840 United States presidential election in Maine took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Maine voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Maine by a margin of 0.46%.

Results

United States presidential election in Maine, 1840[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	46,612	50.23%	10	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	46,190	49.77%	0	0.00%
Total				92,802	100.00%	10	100.00%

References

1. "1840 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved 23 December 2013.