United States presidential election in Vermont, 1840

October 30 - December 2, 1840

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

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The 1840 United States presidential election in Vermont took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 28.43%.

Results

United States presidential election in Vermont, 1840^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	32,445	63.90%	7	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	18,009	35.47%	0	0.00%
	Liberty	James G. Birney of New York	Thomas Earle of Pennsylvania	319	0.63%	0	0.00%
Total				50,773	100.00%	7	100.00%

State Results of the 1840 U.S. presidential election

Candidates	William Henry Harrison Martin Van Buren James G. Birney

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1840 elections	House Senate Gubernatorial

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