United States presidential election in Massachusetts, 1840

United States presidential election in Massachusetts, 1840
Massachusetts
October 30 - December 2, 1840

 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 14 0
Popular vote 72,852 52,355
Percentage 57.44 41.28

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig


The 1840 United States presidential election in Massachusetts took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose fourteen representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Massachusetts by a margin of 16.16%.

Results

United States presidential election in Massachusetts, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 72,852 57.44% 14 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 52,355 41.28% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 1,618 1.28% 0 0.00%
Total 126,825 100.00% 14 100.00%

References

  1. "1840 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.
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