United States presidential election in Vermont, 1828
Main article: United States presidential election, 1828
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The 1828 United States presidential election in Vermont took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Vermont by a margin of 50.46%.
Results
United States presidential election in Vermont, 1828[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
National Republican | John Quincy Adams | 25,363 | 75.23% | 7 | |
Democratic | Andrew Jackson | 8,350 | 24.77% | 0 | |
Totals | 33,713 | 100.0% | 7 | ||
References
- ↑ "1828 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 28 February 2013.
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