Vermont gubernatorial election, 1916
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The Vermont gubernatorial election of 1916 took place on November 7, 1916. Incumbent Republican Charles W. Gates, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Horace F. Graham defeated Democratic candidate William B. Mayo to succeed him.
Republican primary
Results
Party | Candidate | Votes | % | ± | |
---|---|---|---|---|---|
Republican | Horace F. Graham | 33,244 | 99.9 | ||
Republican | Other | 37 | 0.1 | ||
Total votes | 33,281 | 100 | |||
Democratic primary
Results
Party | Candidate | Votes | % | ± | |
---|---|---|---|---|---|
Democratic | William B. Mayo | 3,562 | 99.9 | ||
Democratic | Other | 1 | 0.0 | ||
Total votes | 3,563 | 100 | |||
General election
Results
Party | Candidate | Votes | % | ± | |
---|---|---|---|---|---|
Republican | Horace F. Graham | 43,265 | 71.1 | ||
Democratic | William B. Mayo | 15,789 | 25.9 | ||
Socialist | W. R. Rowland | 920 | 1.5 | ||
Prohibition | Lester W. Hanson | 876 | 1.4 | ||
N/A | Other | 4 | 0.0 | ||
Total votes | 60,854 | 100 | |||
References
- ↑ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
- 1 2 "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.
- ↑ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.
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