United States presidential election in Vermont, 1844

November 1 - December 4, 1840

President before election

John Tyler
Independent

Elected President

James K. Polk
Democratic

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The 1844 United States presidential election in Vermont took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk and Liberty candidate James G. Birney. Clay won Vermont by a margin of 17.88%.

Results

United States presidential election in Vermont, 1844^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	26,780	54.84%	6	100.00%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	18,049	36.96%	0	0.00%
	Liberty	James G. Birney of Michigan	Thomas Morris of Ohio	3,970	8.13%	0	0.00%
	N/A	Others	Others	30	0.06%	0	0.00%
Total				48,829	100.00%	6	100.00%

State Results of the 1844 U.S. presidential election

Candidates	James K. Polk Henry Clay James G. Birney

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1844 elections	House Senate Gubernatorial

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