Belgian general election, 1888
Belgian general election, 1888
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12 June 1888 (1888-06-12) |
|
|
Government before election
Beernaert Government
Catholic |
Elected Government
Beernaert Government
Catholic |
|
Partial general elections were held in Belgium on 12 June 1888.[1][2] The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate.[2]
Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.
Results
Chamber of Representatives
Party |
Votes |
% |
Seats |
Won |
Total |
+/– |
Catholic Party | 31,273 | 58.4 | 66 | 98 | 0 |
Liberal Party | 19,967 | 37.3 | 3 | 40 | 0 |
Others | 2,277 | 4.3 | 0 | 0 | New |
Invalid/blank votes | | – | – | – | – |
Total | 53,517 | 100 | 69 | 138 | 0 |
Registered voters/turnout | 73,276 | | – | – | – |
Source: Mackie & Rose,[3] Sternberger et al |
Senate
References
- ↑ Codebook Constituency-level Elections Archive, 2003
- 1 2 Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
- ↑ Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51