Belgian general election, 1890
Belgian general election, 1890
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10 June 1890 (1890-06-10) |
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Government before election
Beernaert Government
Catholic |
Elected Government
Beernaert Government
Catholic |
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Partial general elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890 after the death of Edmond van der Linden d'Hooghvorst (d).[3] Winand Heynen (d) was elected to replace him.
Results
Chamber of Representatives
Party |
Votes |
% |
Seats |
Won |
Total |
+/– |
Liberal Party | 20,829 | 54.5 | 40 | 44 | +4 |
Catholic Party | 17,253 | 45.2 | 29 | 94 | –4 |
Belgian Labour Party | 98 | 0.3 | 0 | 0 | New |
Others | 30 | 0.1 | 0 | 0 | 0 |
Invalid/blank votes | | – | – | – | – |
Total | 38,210 | 100 | 69 | 138 | 0 |
Registered voters/turnout | 59,452 | | – | – | – |
Source: Mackie & Rose,[4] Sternberger et al. |
Constituencies
The distribution of seats among the electoral districts was as follows:[5]
References