United States presidential election in Pennsylvania, 1860

United States presidential election in Pennsylvania, 1860
November 6, 1860

Nominee Abraham Lincoln John C. Breckinridge
Party Republican Southern Democratic
Home state Illinois Kentucky
Running mate Hannibal Hamlin Joseph Lane
Electoral vote 27 0
Popular vote 268,030 178,871
Percentage 56.26% 37.54%

President before election

James Buchanan

Elected President

Abraham Lincoln

The 1860 United States presidential election in Pennsylvania took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose 27 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican candidate, Abraham Lincoln, over the Southern Democratic candidate, John C. Breckinridge. Lincoln won Pennsylvania by a margin of 18.72%.


United States presidential election in Pennsylvania, 1860[1]
Party Candidate Votes Percentage Electoral votes
Republican Abraham Lincoln 268,030 56.26% 27
Southern Democratic John C. Breckinridge 178,871 37.54% 0
Democratic Stephen A. Douglas 16,765 3.52% 0
Constitutional Union John Bell 12,776 2.68% 0
Totals 476,442 100.0% 27


  1. "1860 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 3 August 2012.
This article is issued from Wikipedia - version of the 2/28/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.