United States presidential election in Pennsylvania, 1884

United States presidential election in Pennsylvania, 1884
Pennsylvania
November 4, 1884

 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 30 0
Popular vote 478,804 392,785
Percentage 52.97% 43.46%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Pennsylvania took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Pennsylvania by a margin of 9.51%.

Results

United States presidential election in Pennsylvania, 1884[1]
Party Candidate Votes Percentage Electoral votes
Republican James G. Blaine 478,804 52.97% 30
Democratic Grover Cleveland 392,785 43.46% 0
Greenback Labor Benjamin Butler 16,992 1.88% 0
Prohibition John St. John 15,283 1.69% 0
Totals 903,864 100.0% 30

References

  1. "1884 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 1 August 2012.
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